Solve F=11/6-(-3/4-5/6)

$$F = \frac { 11 } { 6 } - ( \frac { - 3 } { 4 } - \frac { 5 } { 6 } )$$

Solve for F

$$F = \frac{41}{12} = 3\frac{5}{12} \approx 3.416666667$$

Steps for Solving Linear Equation

Fraction \frac{-3}{4} can be rewritten as -\frac{3}{4} by extracting the negative sign.

$$F=\frac{11}{6}-\left(-\frac{3}{4}-\frac{5}{6}\right)$$

Least common multiple of 4 and 6 is 12. Convert -\frac{3}{4} and \frac{5}{6} to fractions with denominator 12.

$$F=\frac{11}{6}-\left(-\frac{9}{12}-\frac{10}{12}\right)$$

Since -\frac{9}{12} and \frac{10}{12} have the same denominator, subtract them by subtracting their numerators.

$$F=\frac{11}{6}-\frac{-9-10}{12}$$

Subtract 10 from -9 to get -19.

$$F=\frac{11}{6}-\left(-\frac{19}{12}\right)$$

The opposite of -\frac{19}{12} is \frac{19}{12}.

$$F=\frac{11}{6}+\frac{19}{12}$$

Least common multiple of 6 and 12 is 12. Convert \frac{11}{6} and \frac{19}{12} to fractions with denominator 12.

$$F=\frac{22}{12}+\frac{19}{12}$$

Since \frac{22}{12} and \frac{19}{12} have the same denominator, add them by adding their numerators.

$$F=\frac{22+19}{12}$$

Add 22 and 19 to get 41.

$$F=\frac{41}{12}$$

Assign F

$$F≔\frac{41}{12}$$