Solve for E
\left\{\begin{matrix}E=\frac{-F+H-20k-2}{10k}\text{, }&k\neq 0\\E\in \mathrm{R}\text{, }&F=H-2\text{ and }k=0\end{matrix}\right.
Solve for F
F=-10Ek+H-20k-2
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H-10k\left(E+2\right)=F+2
Swap sides so that all variable terms are on the left hand side.
H-10kE-20k=F+2
Use the distributive property to multiply -10k by E+2.
-10kE-20k=F+2-H
Subtract H from both sides.
-10kE=F+2-H+20k
Add 20k to both sides.
\left(-10k\right)E=F-H+20k+2
The equation is in standard form.
\frac{\left(-10k\right)E}{-10k}=\frac{F-H+20k+2}{-10k}
Divide both sides by -10k.
E=\frac{F-H+20k+2}{-10k}
Dividing by -10k undoes the multiplication by -10k.
E=-\frac{F-H+20k+2}{10k}
Divide F-H+2+20k by -10k.
F=H-10k\left(E+2\right)-2
Subtract 2 from both sides.
F=H-10kE-20k-2
Use the distributive property to multiply -10k by E+2.
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