E d = \frac { 2,8 } { 10 } \times \frac { 7 - 10 } { 3,3 - 2,8 }
Solve for E
E=-\frac{42}{25d}
d\neq 0
Solve for d
d=-\frac{42}{25E}
E\neq 0
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Ed=\frac{28}{100}\times \left(\frac{7-10}{3,3-2,8}\right)
Expand \frac{2,8}{10} by multiplying both numerator and the denominator by 10.
Ed=\frac{7}{25}\times \left(\frac{7-10}{3,3-2,8}\right)
Reduce the fraction \frac{28}{100} to lowest terms by extracting and canceling out 4.
Ed=\frac{7}{25}\times \left(\frac{-3}{3,3-2,8}\right)
Subtract 10 from 7 to get -3.
Ed=\frac{7}{25}\times \left(\frac{-3}{0,5}\right)
Subtract 2,8 from 3,3 to get 0,5.
Ed=\frac{7}{25}\times \left(\frac{-30}{5}\right)
Expand \frac{-3}{0,5} by multiplying both numerator and the denominator by 10.
Ed=\frac{7}{25}\times \left(-6\right)
Divide -30 by 5 to get -6.
dE=-\frac{42}{25}
The equation is in standard form.
\frac{dE}{d}=-\frac{\frac{42}{25}}{d}
Divide both sides by d.
E=-\frac{\frac{42}{25}}{d}
Dividing by d undoes the multiplication by d.
E=-\frac{42}{25d}
Divide -\frac{42}{25} by d.
Ed=\frac{28}{100}\times \left(\frac{7-10}{3,3-2,8}\right)
Expand \frac{2,8}{10} by multiplying both numerator and the denominator by 10.
Ed=\frac{7}{25}\times \left(\frac{7-10}{3,3-2,8}\right)
Reduce the fraction \frac{28}{100} to lowest terms by extracting and canceling out 4.
Ed=\frac{7}{25}\times \left(\frac{-3}{3,3-2,8}\right)
Subtract 10 from 7 to get -3.
Ed=\frac{7}{25}\times \left(\frac{-3}{0,5}\right)
Subtract 2,8 from 3,3 to get 0,5.
Ed=\frac{7}{25}\times \left(\frac{-30}{5}\right)
Expand \frac{-3}{0,5} by multiplying both numerator and the denominator by 10.
Ed=\frac{7}{25}\times \left(-6\right)
Divide -30 by 5 to get -6.
Ed=-\frac{42}{25}
The equation is in standard form.
\frac{Ed}{E}=-\frac{\frac{42}{25}}{E}
Divide both sides by E.
d=-\frac{\frac{42}{25}}{E}
Dividing by E undoes the multiplication by E.
d=-\frac{42}{25E}
Divide -\frac{42}{25} by E.
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