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\frac{\left(\left(x+2\right)^{2}-9\right)\times 18x}{\left(3x-3\right)\left(3x^{2}+15x\right)}
Divide \frac{\left(x+2\right)^{2}-9}{3x-3} by \frac{3x^{2}+15x}{18x} by multiplying \frac{\left(x+2\right)^{2}-9}{3x-3} by the reciprocal of \frac{3x^{2}+15x}{18x}.
\frac{18x\left(x-1\right)\left(x+5\right)}{3^{2}x\left(x-1\right)\left(x+5\right)}
Factor the expressions that are not already factored.
\frac{18}{3^{2}}
Cancel out x\left(x-1\right)\left(x+5\right) in both numerator and denominator.
\frac{18}{9}
Calculate 3 to the power of 2 and get 9.
2
Divide 18 by 9 to get 2.