Solve E=2+2/2-2/3/4-frac{1{2}+1/3}

$$E = \frac { 2 + \frac { 2 } { 2 } - \frac { 2 } { 3 } } { 4 - \frac { 1 } { 2 } + \frac { 1 } { 3 } }$$

Solve for E

$$E=\frac{14}{23}\approx 0.608695652$$

Steps for Solving Linear Equation

Divide 2 by 2 to get 1.

$$E=\frac{2+1-\frac{2}{3}}{4-\frac{1}{2}+\frac{1}{3}}$$

Add 2 and 1 to get 3.

$$E=\frac{3-\frac{2}{3}}{4-\frac{1}{2}+\frac{1}{3}}$$

Convert 3 to fraction \frac{9}{3}.

$$E=\frac{\frac{9}{3}-\frac{2}{3}}{4-\frac{1}{2}+\frac{1}{3}}$$

Since \frac{9}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$E=\frac{\frac{9-2}{3}}{4-\frac{1}{2}+\frac{1}{3}}$$

Subtract 2 from 9 to get 7.

$$E=\frac{\frac{7}{3}}{4-\frac{1}{2}+\frac{1}{3}}$$

Convert 4 to fraction \frac{8}{2}.

$$E=\frac{\frac{7}{3}}{\frac{8}{2}-\frac{1}{2}+\frac{1}{3}}$$

Since \frac{8}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$E=\frac{\frac{7}{3}}{\frac{8-1}{2}+\frac{1}{3}}$$

Subtract 1 from 8 to get 7.

$$E=\frac{\frac{7}{3}}{\frac{7}{2}+\frac{1}{3}}$$

Least common multiple of 2 and 3 is 6. Convert \frac{7}{2} and \frac{1}{3} to fractions with denominator 6.

$$E=\frac{\frac{7}{3}}{\frac{21}{6}+\frac{2}{6}}$$

Since \frac{21}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$E=\frac{\frac{7}{3}}{\frac{21+2}{6}}$$

Add 21 and 2 to get 23.

$$E=\frac{\frac{7}{3}}{\frac{23}{6}}$$

Divide \frac{7}{3} by \frac{23}{6} by multiplying \frac{7}{3} by the reciprocal of \frac{23}{6}.

$$E=\frac{7}{3}\times \frac{6}{23}$$

Multiply \frac{7}{3} times \frac{6}{23} by multiplying numerator times numerator and denominator times denominator.

$$E=\frac{7\times 6}{3\times 23}$$

Do the multiplications in the fraction \frac{7\times 6}{3\times 23}.

$$E=\frac{42}{69}$$

Reduce the fraction \frac{42}{69} to lowest terms by extracting and canceling out 3.

$$E=\frac{14}{23}$$

Assign E

$$E≔\frac{14}{23}$$