Solve for E
E = \frac{18}{7} = 2\frac{4}{7} \approx 2.571428571
Assign E
E≔\frac{18}{7}
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E=\frac{-\frac{3}{2}}{\frac{8}{12}-\frac{5}{4}}
Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.
E=\frac{-\frac{3}{2}}{\frac{2}{3}-\frac{5}{4}}
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
E=\frac{-\frac{3}{2}}{\frac{8}{12}-\frac{15}{12}}
Least common multiple of 3 and 4 is 12. Convert \frac{2}{3} and \frac{5}{4} to fractions with denominator 12.
E=\frac{-\frac{3}{2}}{\frac{8-15}{12}}
Since \frac{8}{12} and \frac{15}{12} have the same denominator, subtract them by subtracting their numerators.
E=\frac{-\frac{3}{2}}{-\frac{7}{12}}
Subtract 15 from 8 to get -7.
E=-\frac{3}{2}\left(-\frac{12}{7}\right)
Divide -\frac{3}{2} by -\frac{7}{12} by multiplying -\frac{3}{2} by the reciprocal of -\frac{7}{12}.
E=\frac{-3\left(-12\right)}{2\times 7}
Multiply -\frac{3}{2} times -\frac{12}{7} by multiplying numerator times numerator and denominator times denominator.
E=\frac{36}{14}
Do the multiplications in the fraction \frac{-3\left(-12\right)}{2\times 7}.
E=\frac{18}{7}
Reduce the fraction \frac{36}{14} to lowest terms by extracting and canceling out 2.
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