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Solve for C
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Solve for D
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DC=\frac{\frac{1}{2}\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{\frac{1}{2}\sqrt{2}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
DC=\frac{\frac{1}{2}\sqrt{2}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
DC=\frac{\frac{1}{2}\sqrt{6}}{3}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
DC=\frac{1}{6}\sqrt{6}
Divide \frac{1}{2}\sqrt{6} by 3 to get \frac{1}{6}\sqrt{6}.
DC=\frac{\sqrt{6}}{6}
The equation is in standard form.
\frac{DC}{D}=\frac{\sqrt{6}}{6D}
Divide both sides by D.
C=\frac{\sqrt{6}}{6D}
Dividing by D undoes the multiplication by D.
DC=\frac{\frac{1}{2}\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{\frac{1}{2}\sqrt{2}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
DC=\frac{\frac{1}{2}\sqrt{2}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
DC=\frac{\frac{1}{2}\sqrt{6}}{3}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
DC=\frac{1}{6}\sqrt{6}
Divide \frac{1}{2}\sqrt{6} by 3 to get \frac{1}{6}\sqrt{6}.
CD=\frac{\sqrt{6}}{6}
The equation is in standard form.
\frac{CD}{C}=\frac{\sqrt{6}}{6C}
Divide both sides by C.
D=\frac{\sqrt{6}}{6C}
Dividing by C undoes the multiplication by C.