Solve D=3^{2^{0}}+5^{2^3^0}+5^25^0

$$D = 3 ^ { 2 ^ { 0 } } + 5 ^ { 2 ^ { 3 ^ { 0 } } } + 5 ^ { 25 ^ { 0 } }$$

Solve for D

$$D=33$$

Steps for Solving Linear Equation

Calculate 2 to the power of 0 and get 1.

$$D=3^{1}+5^{2^{3^{0}}}+5^{25^{0}}$$

Calculate 3 to the power of 1 and get 3.

$$D=3+5^{2^{3^{0}}}+5^{25^{0}}$$

Calculate 3 to the power of 0 and get 1.

$$D=3+5^{2^{1}}+5^{25^{0}}$$

Calculate 2 to the power of 1 and get 2.

$$D=3+5^{2}+5^{25^{0}}$$

Calculate 5 to the power of 2 and get 25.

$$D=3+25+5^{25^{0}}$$

Add 3 and 25 to get 28.

$$D=28+5^{25^{0}}$$

Calculate 25 to the power of 0 and get 1.

$$D=28+5^{1}$$

Calculate 5 to the power of 1 and get 5.

$$D=28+5$$

Add 28 and 5 to get 33.

$$D=33$$

Assign D

$$D≔33$$