Solve D=(-3)^2*(-1)^3*(-2)^3*(-1)^4

$$D = ( - 3 ) ^ { 2 } \cdot ( - 1 ) ^ { 3 } \cdot ( - 2 ) ^ { 3 } \cdot ( - 1 ) ^ { 4 }$$

Solve for D

$$D=72$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 3 and 4 to get 7.

$$D=\left(-3\right)^{2}\left(-1\right)^{7}\left(-2\right)^{3}$$

Calculate -3 to the power of 2 and get 9.

$$D=9\left(-1\right)^{7}\left(-2\right)^{3}$$

Calculate -1 to the power of 7 and get -1.

$$D=9\left(-1\right)\left(-2\right)^{3}$$

Multiply 9 and -1 to get -9.

$$D=-9\left(-2\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$D=-9\left(-8\right)$$

Multiply -9 and -8 to get 72.

$$D=72$$

Assign D

$$D≔72$$