Solve D=sqrt{(3-(-7))^2+(1-(-1))^2}

$$D = \sqrt { ( 3 - ( - 7 ) ) ^ { 2 } + ( 1 - ( - 1 ) ) ^ { 2 } }$$

Solve for D

$$D=2\sqrt{26}\approx 10.198039027$$

Steps for Solving Linear Equation

The opposite of -7 is 7.

$$D=\sqrt{\left(3+7\right)^{2}+\left(1-\left(-1\right)\right)^{2}}$$

Add 3 and 7 to get 10.

$$D=\sqrt{10^{2}+\left(1-\left(-1\right)\right)^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$D=\sqrt{100+\left(1-\left(-1\right)\right)^{2}}$$

The opposite of -1 is 1.

$$D=\sqrt{100+\left(1+1\right)^{2}}$$

Add 1 and 1 to get 2.

$$D=\sqrt{100+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$D=\sqrt{100+4}$$

Add 100 and 4 to get 104.

$$D=\sqrt{104}$$

Factor 104=2^{2}\times 26. Rewrite the square root of the product \sqrt{2^{2}\times 26} as the product of square roots \sqrt{2^{2}}\sqrt{26}. Take the square root of 2^{2}.

$$D=2\sqrt{26}$$

Assign D

$$D≔2\sqrt{26}$$