Solve D=8*x^9*x^18/9*x^13*x^12text{3a}x=3

$$D = \frac { 8 \cdot x ^ { 9 } \cdot x ^ { 18 } } { 9 \cdot x ^ { 13 } \cdot x ^ { 12 } } \text { 3a } x = 3$$

Solve for D, x

$$x=3$$

$$D=8$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$D=\frac{8\times 3^{9}\times 3^{18}}{9\times 3^{13}\times 3^{12}}$$

To multiply powers of the same base, add their exponents. Add 9 and 18 to get 27.

$$D=\frac{8\times 3^{27}}{9\times 3^{13}\times 3^{12}}$$

To multiply powers of the same base, add their exponents. Add 13 and 12 to get 25.

$$D=\frac{8\times 3^{27}}{9\times 3^{25}}$$

Cancel out 3^{25} in both numerator and denominator.

$$D=\frac{8\times 3^{2}}{9}$$

Calculate 3 to the power of 2 and get 9.

$$D=\frac{8\times 9}{9}$$

Multiply 8 and 9 to get 72.

$$D=\frac{72}{9}$$

Divide 72 by 9 to get 8.

$$D=8$$

The system is now solved.

$$D=8 x=3$$