Solve D=4/7(F+G)

$$D = \frac { 4 } { 7 } ( F + G )$$

Solve for F

$$F=\frac{7D}{4}-G$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{4}{7} by F+G.

$$D=\frac{4}{7}F+\frac{4}{7}G$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{4}{7}F+\frac{4}{7}G=D$$

Subtract \frac{4}{7}G from both sides.

$$\frac{4}{7}F=D-\frac{4}{7}G$$

The equation is in standard form.

$$\frac{4}{7}F=-\frac{4G}{7}+D$$

Divide both sides of the equation by \frac{4}{7}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{4}{7}F}{\frac{4}{7}}=\frac{-\frac{4G}{7}+D}{\frac{4}{7}}$$

Dividing by \frac{4}{7} undoes the multiplication by \frac{4}{7}.

$$F=\frac{-\frac{4G}{7}+D}{\frac{4}{7}}$$

Divide D-\frac{4G}{7} by \frac{4}{7} by multiplying D-\frac{4G}{7} by the reciprocal of \frac{4}{7}.

$$F=\frac{7D}{4}-G$$

Solve for D

$$D=\frac{4\left(F+G\right)}{7}$$

Solution Steps

Use the distributive property to multiply \frac{4}{7} by F+G.

$$D=\frac{4}{7}F+\frac{4}{7}G$$