Solve D=10/14div(40/42+5/7)

$$D = \frac { 10 } { 14 } \div ( \frac { 40 } { 42 } + \frac { 5 } { 7 } )$$

Solve for D

$$D=\frac{3}{7}\approx 0.428571429$$

Steps for Solving Linear Equation

Reduce the fraction \frac{10}{14} to lowest terms by extracting and canceling out 2.

$$D=\frac{\frac{5}{7}}{\frac{40}{42}+\frac{5}{7}}$$

Reduce the fraction \frac{40}{42} to lowest terms by extracting and canceling out 2.

$$D=\frac{\frac{5}{7}}{\frac{20}{21}+\frac{5}{7}}$$

Least common multiple of 21 and 7 is 21. Convert \frac{20}{21} and \frac{5}{7} to fractions with denominator 21.

$$D=\frac{\frac{5}{7}}{\frac{20}{21}+\frac{15}{21}}$$

Since \frac{20}{21} and \frac{15}{21} have the same denominator, add them by adding their numerators.

$$D=\frac{\frac{5}{7}}{\frac{20+15}{21}}$$

Add 20 and 15 to get 35.

$$D=\frac{\frac{5}{7}}{\frac{35}{21}}$$

Reduce the fraction \frac{35}{21} to lowest terms by extracting and canceling out 7.

$$D=\frac{\frac{5}{7}}{\frac{5}{3}}$$

Divide \frac{5}{7} by \frac{5}{3} by multiplying \frac{5}{7} by the reciprocal of \frac{5}{3}.

$$D=\frac{5}{7}\times \frac{3}{5}$$

Multiply \frac{5}{7} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$D=\frac{5\times 3}{7\times 5}$$

Cancel out 5 in both numerator and denominator.

$$D=\frac{3}{7}$$

Assign D

$$D≔\frac{3}{7}$$