Solve D=1/2CD

$$D = \frac { 1 } { 2 } C D$$

Solve for C

$$\left\{\begin{matrix}\\C=2\text{, }&\text{unconditionally}\\C\in \mathrm{R}\text{, }&D=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}CD=D$$

The equation is in standard form.

$$\frac{D}{2}C=D$$

Divide both sides by \frac{1}{2}D.

$$\frac{2\times \frac{D}{2}C}{D}=\frac{2D}{D}$$

Dividing by \frac{1}{2}D undoes the multiplication by \frac{1}{2}D.

$$C=\frac{2D}{D}$$

Divide D by \frac{1}{2}D.

$$C=2$$

Solve for D

$$\left\{\begin{matrix}\\D=0\text{, }&\text{unconditionally}\\D\in \mathrm{R}\text{, }&C=2\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract \frac{1}{2}CD from both sides.

$$D-\frac{1}{2}CD=0$$

Combine all terms containing D.

$$\left(1-\frac{1}{2}C\right)D=0$$

The equation is in standard form.

$$\left(-\frac{C}{2}+1\right)D=0$$

Divide 0 by 1-\frac{1}{2}C.

$$D=0$$