Solve D=3-1-4*3+7/sqrt{3^2+-4^2}

$$D = \frac{ 3-1-4 \cdot 3+7 }{ \sqrt{ { 3 }^{ 2 } + { -4 }^{ 2 } } }$$

Solve for D

$$D=-\frac{3}{5}=-0.6$$

Steps for Solving Linear Equation

Subtract 1 from 3 to get 2.

$$D=\frac{2-4\times 3+7}{\sqrt{3^{2}+\left(-4\right)^{2}}}$$

Multiply 4 and 3 to get 12.

$$D=\frac{2-12+7}{\sqrt{3^{2}+\left(-4\right)^{2}}}$$

Subtract 12 from 2 to get -10.

$$D=\frac{-10+7}{\sqrt{3^{2}+\left(-4\right)^{2}}}$$

Add -10 and 7 to get -3.

$$D=\frac{-3}{\sqrt{3^{2}+\left(-4\right)^{2}}}$$

Calculate 3 to the power of 2 and get 9.

$$D=\frac{-3}{\sqrt{9+\left(-4\right)^{2}}}$$

Calculate -4 to the power of 2 and get 16.

$$D=\frac{-3}{\sqrt{9+16}}$$

Add 9 and 16 to get 25.

$$D=\frac{-3}{\sqrt{25}}$$

Calculate the square root of 25 and get 5.

$$D=\frac{-3}{5}$$

Fraction \frac{-3}{5} can be rewritten as -\frac{3}{5} by extracting the negative sign.

$$D=-\frac{3}{5}$$

Assign D

$$D≔-\frac{3}{5}$$