Solve Cx(120)=10x+100

$$Cx(120) = 10x+100$$

Solve for C

$$C=\frac{1}{12}+\frac{5}{6x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

The equation is in standard form.

$$120xC=10x+100$$

Divide both sides by 120x.

$$\frac{120xC}{120x}=\frac{10x+100}{120x}$$

Dividing by 120x undoes the multiplication by 120x.

$$C=\frac{10x+100}{120x}$$

Divide 100+10x by 120x.

$$C=\frac{1}{12}+\frac{5}{6x}$$

Solve for x

$$x=\frac{10}{12C-1}$$

$$C\neq \frac{1}{12}$$

Steps for Solving Linear Equation

Subtract 10x from both sides.

$$Cx\times 120-10x=100$$

Combine all terms containing x.

$$\left(C\times 120-10\right)x=100$$

The equation is in standard form.

$$\left(120C-10\right)x=100$$

Divide both sides by 120C-10.

$$\frac{\left(120C-10\right)x}{120C-10}=\frac{100}{120C-10}$$

Dividing by 120C-10 undoes the multiplication by 120C-10.

$$x=\frac{100}{120C-10}$$

Divide 100 by 120C-10.

$$x=\frac{10}{12C-1}$$