Solve for C
C=5x^{2}-2x+2+\frac{8}{x}
x\neq 0
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xC=5x^{3}-2x^{2}+2x+8
The equation is in standard form.
\frac{xC}{x}=\frac{5x^{3}-2x^{2}+2x+8}{x}
Divide both sides by x.
C=\frac{5x^{3}-2x^{2}+2x+8}{x}
Dividing by x undoes the multiplication by x.
C=5x^{2}-2x+2+\frac{8}{x}
Divide 5x^{3}-2x^{2}+2x+8 by x.
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