Solve Cl=1000[1+(10/100)]^3-1000

$$C l = 1000 [ 1 + ( 10 / 100 ) ] ^ { 3 } - 1000$$

Solve for C

$$C=\frac{331}{l}$$

$$l\neq 0$$

Steps for Solving Linear Equation

Reduce the fraction \frac{10}{100} to lowest terms by extracting and canceling out 10.

$$Cl=1000\left(1+\frac{1}{10}\right)^{3}-1000$$

Add 1 and \frac{1}{10} to get \frac{11}{10}.

$$Cl=1000\times \left(\frac{11}{10}\right)^{3}-1000$$

Calculate \frac{11}{10} to the power of 3 and get \frac{1331}{1000}.

$$Cl=1000\times \frac{1331}{1000}-1000$$

Multiply 1000 and \frac{1331}{1000} to get 1331.

$$Cl=1331-1000$$

Subtract 1000 from 1331 to get 331.

$$Cl=331$$

The equation is in standard form.

$$lC=331$$

Divide both sides by l.

$$\frac{lC}{l}=\frac{331}{l}$$

Dividing by l undoes the multiplication by l.

$$C=\frac{331}{l}$$

Solve for l

$$l=\frac{331}{C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Reduce the fraction \frac{10}{100} to lowest terms by extracting and canceling out 10.

$$Cl=1000\left(1+\frac{1}{10}\right)^{3}-1000$$

Add 1 and \frac{1}{10} to get \frac{11}{10}.

$$Cl=1000\times \left(\frac{11}{10}\right)^{3}-1000$$

Calculate \frac{11}{10} to the power of 3 and get \frac{1331}{1000}.

$$Cl=1000\times \frac{1331}{1000}-1000$$

Multiply 1000 and \frac{1331}{1000} to get 1331.

$$Cl=1331-1000$$

Subtract 1000 from 1331 to get 331.

$$Cl=331$$

Divide both sides by C.

$$\frac{Cl}{C}=\frac{331}{C}$$

Dividing by C undoes the multiplication by C.

$$l=\frac{331}{C}$$