Solve for A
\left\{\begin{matrix}A=\frac{2CM}{B}\text{, }&B\neq 0\\A\in \mathrm{R}\text{, }&\left(C=0\text{ or }M=0\right)\text{ and }B=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=\frac{2CM}{A}\text{, }&A\neq 0\\B\in \mathrm{R}\text{, }&\left(C=0\text{ or }M=0\right)\text{ and }A=0\end{matrix}\right.
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\frac{1}{2}AB=CM
Swap sides so that all variable terms are on the left hand side.
\frac{B}{2}A=CM
The equation is in standard form.
\frac{2\times \frac{B}{2}A}{B}=\frac{2CM}{B}
Divide both sides by \frac{1}{2}B.
A=\frac{2CM}{B}
Dividing by \frac{1}{2}B undoes the multiplication by \frac{1}{2}B.
\frac{1}{2}AB=CM
Swap sides so that all variable terms are on the left hand side.
\frac{A}{2}B=CM
The equation is in standard form.
\frac{2\times \frac{A}{2}B}{A}=\frac{2CM}{A}
Divide both sides by \frac{1}{2}A.
B=\frac{2CM}{A}
Dividing by \frac{1}{2}A undoes the multiplication by \frac{1}{2}A.
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