Solve C(x)=2x^2-3.700eR(x)=120x

$$C ( x ) = 2 x ^ { 2 } - 3.700 e R ( x ) = 120 x$$

Solve for R (complex solution)

$$\left\{\begin{matrix}\\R=-\frac{20\left(60-x\right)}{37e}\text{, }&\text{unconditionally}\\R\in \mathrm{C}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -1 and 3.7 to get -3.7.

$$2x^{2}-3.7eRx=120x$$

Subtract 2x^{2} from both sides.

$$-3.7eRx=120x-2x^{2}$$

The equation is in standard form.

$$\left(-\frac{37ex}{10}\right)R=120x-2x^{2}$$

Divide both sides by -3.7ex.

$$\frac{\left(-\frac{37ex}{10}\right)R}{-\frac{37ex}{10}}=\frac{2x\left(60-x\right)}{-\frac{37ex}{10}}$$

Dividing by -3.7ex undoes the multiplication by -3.7ex.

$$R=\frac{2x\left(60-x\right)}{-\frac{37ex}{10}}$$

Divide 2x\left(60-x\right) by -3.7ex.

$$R=-\frac{20\left(60-x\right)}{37e}$$

Solve for R

$$\left\{\begin{matrix}\\R=-\frac{20\left(60-x\right)}{37e}\text{, }&\text{unconditionally}\\R\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -1 and 3.7 to get -3.7.

$$2x^{2}-3.7eRx=120x$$

Subtract 2x^{2} from both sides.

$$-3.7eRx=120x-2x^{2}$$

The equation is in standard form.

$$\left(-\frac{37ex}{10}\right)R=120x-2x^{2}$$

Divide both sides by -3.7ex.

$$\frac{\left(-\frac{37ex}{10}\right)R}{-\frac{37ex}{10}}=\frac{2x\left(60-x\right)}{-\frac{37ex}{10}}$$

Dividing by -3.7ex undoes the multiplication by -3.7ex.

$$R=\frac{2x\left(60-x\right)}{-\frac{37ex}{10}}$$

Divide 2x\left(60-x\right) by -3.7ex.

$$R=-\frac{20\left(60-x\right)}{37e}$$

Solve for x

$$x=\frac{37eR}{20}+60$$

$$x=0$$