Solve C(x)=06x^2-360x+59099

$$C ( x ) = 06 x ^ { 2 } - 360 x + 59099$$

Evaluate

$$59099-360x$$

Solution Steps

Multiply 0 and 6 to get 0.

$$0x^{2}-360x+59099$$

Anything times zero gives zero.

$$0-360x+59099$$

Add 0 and 59099 to get 59099.

$$59099-360x$$

Differentiate w.r.t. x

$$-360$$

Steps Using Derivative Rule for Sum

Multiply 0 and 6 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0x^{2}-360x+59099)$$

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0-360x+59099)$$

Add 0 and 59099 to get 59099.

$$\frac{\mathrm{d}}{\mathrm{d}x}(59099-360x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-360x^{1-1}$$

Subtract 1 from 1.

$$-360x^{0}$$

For any term t except 0, t^{0}=1.

$$-360$$