Solve for C
\left\{\begin{matrix}C=\frac{F+13}{a}\text{, }&a\neq 0\\C\in \mathrm{R}\text{, }&F=-13\text{ and }a=0\end{matrix}\right.
Solve for F
F=Ca-13
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Ca=13+F
Add F to both sides.
aC=F+13
The equation is in standard form.
\frac{aC}{a}=\frac{F+13}{a}
Divide both sides by a.
C=\frac{F+13}{a}
Dividing by a undoes the multiplication by a.
-F=13-Ca
Subtract Ca from both sides.
\frac{-F}{-1}=\frac{13-Ca}{-1}
Divide both sides by -1.
F=\frac{13-Ca}{-1}
Dividing by -1 undoes the multiplication by -1.
F=Ca-13
Divide 13-Ca by -1.
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