Solve for C
C=16n^{2}-5
Solve for n
n=-\frac{\sqrt{C+5}}{4}
n=\frac{\sqrt{C+5}}{4}\text{, }C\geq -5
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C=\left(4n\right)^{2}-1-4
Consider \left(4n+1\right)\left(4n-1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
C=4^{2}n^{2}-1-4
Expand \left(4n\right)^{2}.
C=16n^{2}-1-4
Calculate 4 to the power of 2 and get 16.
C=16n^{2}-5
Subtract 4 from -1 to get -5.
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