Solve C=4*8-32/7*2^3-(5*2)^2

$$C = \frac { 4 \times 8 - 32 } { 7 \times 2 ^ { 3 } - ( 5 \times 2 ) ^ { 2 } }$$

Solve for C

$$C=0$$

Steps for Solving Linear Equation

Multiply 4 and 8 to get 32.

$$C=\frac{32-32}{7\times 2^{3}-\left(5\times 2\right)^{2}}$$

Subtract 32 from 32 to get 0.

$$C=\frac{0}{7\times 2^{3}-\left(5\times 2\right)^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$C=\frac{0}{7\times 8-\left(5\times 2\right)^{2}}$$

Multiply 7 and 8 to get 56.

$$C=\frac{0}{56-\left(5\times 2\right)^{2}}$$

Multiply 5 and 2 to get 10.

$$C=\frac{0}{56-10^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$C=\frac{0}{56-100}$$

Subtract 100 from 56 to get -44.

$$C=\frac{0}{-44}$$

Zero divided by any non-zero number gives zero.

$$C=0$$

Assign C

$$C≔0$$