Solve BO-AB=AA

$$BO - AB = AA$$

Solve for B (complex solution)

$$\left\{\begin{matrix}B=\frac{A^{2}}{O-A}\text{, }&O\neq A\\B\in \mathrm{C}\text{, }&A=0\text{ and }O=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply A and A to get A^{2}.

$$BO-AB=A^{2}$$

Combine all terms containing B.

$$\left(O-A\right)B=A^{2}$$

Divide both sides by O-A.

$$\frac{\left(O-A\right)B}{O-A}=\frac{A^{2}}{O-A}$$

Dividing by O-A undoes the multiplication by O-A.

$$B=\frac{A^{2}}{O-A}$$

Solve for B

$$\left\{\begin{matrix}B=\frac{A^{2}}{O-A}\text{, }&O\neq A\\B\in \mathrm{R}\text{, }&A=0\text{ and }O=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply A and A to get A^{2}.

$$BO-AB=A^{2}$$

Combine all terms containing B.

$$\left(O-A\right)B=A^{2}$$

Divide both sides by O-A.

$$\frac{\left(O-A\right)B}{O-A}=\frac{A^{2}}{O-A}$$

Dividing by O-A undoes the multiplication by O-A.

$$B=\frac{A^{2}}{O-A}$$

Solve for A (complex solution)

$$A=\frac{-\sqrt{B\left(B+4O\right)}-B}{2}$$

$$A=\frac{\sqrt{B\left(B+4O\right)}-B}{2}$$

Solve for A

$$A=\frac{-\sqrt{B\left(B+4O\right)}-B}{2}$$

$$A=\frac{\sqrt{B\left(B+4O\right)}-B}{2}\text{, }\left(B\geq 0\text{ or }B\leq -4O\right)\text{ and }\left(B\leq 0\text{ or }B\geq -4O\right)$$