Solve BE=(15.8)(98)-(17.8)(98)^2/3-(0.71)43(43-1)/98^1/3-23.7(55-43)^3/98

$$B E = ( 15.8 ) ( 98 ) - ( 17.8 ) ( 98 ) ^ { 2 / 3 } - ( 0.71 ) \frac { 43 ( 43 - 1 ) } { 98 ^ { 1 / 3 } } - 23.7 \frac { ( 55 - 43 ) ^ { 3 } } { 98 }$$

Solve for B

$$B=\frac{5539480-151333\times 98^{\frac{2}{3}}}{4900E}$$

$$E\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 98.

$$98BE=98\left(15.8\times 98-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\left(43-1\right)}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Multiply 15.8 and 98 to get 1548.4.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\left(43-1\right)}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Subtract 1 from 43 to get 42.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\times 42}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Multiply 43 and 42 to get 1806.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Subtract 43 from 55 to get 12.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\times 12^{3}$$

Calculate 12 to the power of 3 and get 1728.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\times 1728$$

Multiply 23.7 and 1728 to get 40953.6.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-40953.6$$

Reorder the terms.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{\sqrt[3]{98}}\right)-40953.6$$

Use the distributive property to multiply 98 by 1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{\sqrt[3]{98}}.

$$98BE=151743.2-1744.4\times 98^{\frac{2}{3}}-69.58\times \frac{1806}{\sqrt[3]{98}}-40953.6$$

Subtract 40953.6 from 151743.2 to get 110789.6.

$$98BE=110789.6-1744.4\times 98^{\frac{2}{3}}-69.58\times \frac{1806}{\sqrt[3]{98}}$$

The equation is in standard form.

$$98EB=-\frac{3141537}{25\sqrt[3]{98}}-\frac{8722\times 98^{\frac{2}{3}}}{5}+110789.6$$

Divide both sides by 98E.

$$\frac{98EB}{98E}=\frac{-\frac{7415317}{25\sqrt[3]{98}}+110789.6}{98E}$$

Dividing by 98E undoes the multiplication by 98E.

$$B=\frac{-\frac{7415317}{25\sqrt[3]{98}}+110789.6}{98E}$$

Divide -\frac{7415317}{25\sqrt[3]{98}}+110789.6 by 98E.

$$B=\frac{-\frac{151333}{50\sqrt[3]{98}}+\frac{276974}{245}}{E}$$

Solve for E

$$E=\frac{5539480-151333\times 98^{\frac{2}{3}}}{4900B}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 98.

$$98BE=98\left(15.8\times 98-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\left(43-1\right)}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Multiply 15.8 and 98 to get 1548.4.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\left(43-1\right)}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Subtract 1 from 43 to get 42.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{43\times 42}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Multiply 43 and 42 to get 1806.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\left(55-43\right)^{3}$$

Subtract 43 from 55 to get 12.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\times 12^{3}$$

Calculate 12 to the power of 3 and get 1728.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-23.7\times 1728$$

Multiply 23.7 and 1728 to get 40953.6.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{98^{\frac{1}{3}}}\right)-40953.6$$

Reorder the terms.

$$98BE=98\left(1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{\sqrt[3]{98}}\right)-40953.6$$

Use the distributive property to multiply 98 by 1548.4-17.8\times 98^{\frac{2}{3}}-0.71\times \frac{1806}{\sqrt[3]{98}}.

$$98BE=151743.2-1744.4\times 98^{\frac{2}{3}}-69.58\times \frac{1806}{\sqrt[3]{98}}-40953.6$$

Subtract 40953.6 from 151743.2 to get 110789.6.

$$98BE=110789.6-1744.4\times 98^{\frac{2}{3}}-69.58\times \frac{1806}{\sqrt[3]{98}}$$

The equation is in standard form.

$$98BE=-\frac{3141537}{25\sqrt[3]{98}}-\frac{8722\times 98^{\frac{2}{3}}}{5}+110789.6$$

Divide both sides by 98B.

$$\frac{98BE}{98B}=\frac{-\frac{7415317}{25\sqrt[3]{98}}+110789.6}{98B}$$

Dividing by 98B undoes the multiplication by 98B.

$$E=\frac{-\frac{7415317}{25\sqrt[3]{98}}+110789.6}{98B}$$

Divide -\frac{7415317}{25\sqrt[3]{98}}+110789.6 by 98B.

$$E=\frac{-\frac{151333}{50\sqrt[3]{98}}+\frac{276974}{245}}{B}$$