Solve BA*B+3=57A

$$B A \cdot B + 3 = 57 A$$

Solve for A (complex solution)

$$A=-\frac{3}{B^{2}-57}$$

$$B\neq -\sqrt{57}\text{ and }B\neq \sqrt{57}$$

Steps for Solving Linear Equation

Multiply B and B to get B^{2}.

$$B^{2}A+3=57A$$

Subtract 57A from both sides.

$$B^{2}A+3-57A=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$B^{2}A-57A=-3$$

Combine all terms containing A.

$$\left(B^{2}-57\right)A=-3$$

Divide both sides by B^{2}-57.

$$\frac{\left(B^{2}-57\right)A}{B^{2}-57}=-\frac{3}{B^{2}-57}$$

Dividing by B^{2}-57 undoes the multiplication by B^{2}-57.

$$A=-\frac{3}{B^{2}-57}$$

Solve for A

$$A=-\frac{3}{B^{2}-57}$$

$$|B|\neq \sqrt{57}$$

Steps for Solving Linear Equation

Multiply B and B to get B^{2}.

$$B^{2}A+3=57A$$

Subtract 57A from both sides.

$$B^{2}A+3-57A=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$B^{2}A-57A=-3$$

Combine all terms containing A.

$$\left(B^{2}-57\right)A=-3$$

Divide both sides by B^{2}-57.

$$\frac{\left(B^{2}-57\right)A}{B^{2}-57}=-\frac{3}{B^{2}-57}$$

Dividing by B^{2}-57 undoes the multiplication by B^{2}-57.

$$A=-\frac{3}{B^{2}-57}$$

Solve for B (complex solution)

$$B=-\sqrt{57-\frac{3}{A}}$$

$$B=\sqrt{57-\frac{3}{A}}\text{, }A\neq 0$$

Solve for B

$$B=\sqrt{57-\frac{3}{A}}$$

$$B=-\sqrt{57-\frac{3}{A}}\text{, }A\geq \frac{1}{19}\text{ or }A<0$$