Solve for x
x=\frac{B+15}{5}
Solve for B
B=5\left(x-3\right)
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5x-15=B
Swap sides so that all variable terms are on the left hand side.
5x=B+15
Add 15 to both sides.
\frac{5x}{5}=\frac{B+15}{5}
Divide both sides by 5.
x=\frac{B+15}{5}
Dividing by 5 undoes the multiplication by 5.
x=\frac{B}{5}+3
Divide B+15 by 5.
Examples
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Integration
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Limits
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