Solve B=2sqrt{27}-2sqrt{3}+sqrt{12}

$$B = 2 \sqrt { 27 } - 2 \sqrt { 3 } + \sqrt { 12 }$$

Solve for B

$$B=6\sqrt{3}\approx 10.392304845$$

Steps for Solving Linear Equation

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$B=2\times 3\sqrt{3}-2\sqrt{3}+\sqrt{12}$$

Multiply 2 and 3 to get 6.

$$B=6\sqrt{3}-2\sqrt{3}+\sqrt{12}$$

Combine 6\sqrt{3} and -2\sqrt{3} to get 4\sqrt{3}.

$$B=4\sqrt{3}+\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$B=4\sqrt{3}+2\sqrt{3}$$

Combine 4\sqrt{3} and 2\sqrt{3} to get 6\sqrt{3}.

$$B=6\sqrt{3}$$

Assign B

$$B≔6\sqrt{3}$$