Solve B=(102/9+23/5)-62/9

$$B = ( 10 \frac { 2 } { 9 } + 2 \frac { 3 } { 5 } ) - 6 \frac { 2 } { 9 }$$

Solve for B

$$B = \frac{33}{5} = 6\frac{3}{5} = 6.6$$

Steps for Solving Linear Equation

Multiply 10 and 9 to get 90.

$$B=\frac{90+2}{9}+\frac{2\times 5+3}{5}-\frac{6\times 9+2}{9}$$

Add 90 and 2 to get 92.

$$B=\frac{92}{9}+\frac{2\times 5+3}{5}-\frac{6\times 9+2}{9}$$

Multiply 2 and 5 to get 10.

$$B=\frac{92}{9}+\frac{10+3}{5}-\frac{6\times 9+2}{9}$$

Add 10 and 3 to get 13.

$$B=\frac{92}{9}+\frac{13}{5}-\frac{6\times 9+2}{9}$$

Least common multiple of 9 and 5 is 45. Convert \frac{92}{9} and \frac{13}{5} to fractions with denominator 45.

$$B=\frac{460}{45}+\frac{117}{45}-\frac{6\times 9+2}{9}$$

Since \frac{460}{45} and \frac{117}{45} have the same denominator, add them by adding their numerators.

$$B=\frac{460+117}{45}-\frac{6\times 9+2}{9}$$

Add 460 and 117 to get 577.

$$B=\frac{577}{45}-\frac{6\times 9+2}{9}$$

Multiply 6 and 9 to get 54.

$$B=\frac{577}{45}-\frac{54+2}{9}$$

Add 54 and 2 to get 56.

$$B=\frac{577}{45}-\frac{56}{9}$$

Least common multiple of 45 and 9 is 45. Convert \frac{577}{45} and \frac{56}{9} to fractions with denominator 45.

$$B=\frac{577}{45}-\frac{280}{45}$$

Since \frac{577}{45} and \frac{280}{45} have the same denominator, subtract them by subtracting their numerators.

$$B=\frac{577-280}{45}$$

Subtract 280 from 577 to get 297.

$$B=\frac{297}{45}$$

Reduce the fraction \frac{297}{45} to lowest terms by extracting and canceling out 9.

$$B=\frac{33}{5}$$

Assign B

$$B≔\frac{33}{5}$$