Solve B=sqrt{2-6x}

$$B = \sqrt { 2 - 6 x }$$

Solve for x

$$x=-\frac{B^{2}}{6}+\frac{1}{3}$$

$$B\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{2-6x}=B$$

Square both sides of the equation.

$$-6x+2=B^{2}$$

Subtract 2 from both sides of the equation.

$$-6x+2-2=B^{2}-2$$

Subtracting 2 from itself leaves 0.

$$-6x=B^{2}-2$$

Divide both sides by -6.

$$\frac{-6x}{-6}=\frac{B^{2}-2}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$x=\frac{B^{2}-2}{-6}$$

Divide B^{2}-2 by -6.

$$x=-\frac{B^{2}}{6}+\frac{1}{3}$$

Solve for x (complex solution)

$$x=-\frac{B^{2}}{6}+\frac{1}{3}$$

$$arg(B)<\pi \text{ or }B=0$$

Solve for B

$$B=\sqrt{2-6x}$$

$$x\leq \frac{1}{3}$$