Solve B=frac{-2*10^{-3}*25*(10^2)^2}{50*10^5*(-0.1)*10^-3}

$$B = \frac { - 2 \times 10 ^ { - 3 } \times 25 \times ( 10 ^ { 2 } ) ^ { 2 } } { 50 \times 10 ^ { 5 } \times ( - 0.1 ) \times 10 ^ { - 3 } }$$

Solve for B

$$B=1$$

Steps for Solving Linear Equation

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$B=\frac{-2\times 10^{-3}\times 25\times 10^{4}}{50\times 10^{5}\left(-0.1\right)\times 10^{-3}}$$

To multiply powers of the same base, add their exponents. Add -3 and 4 to get 1.

$$B=\frac{-2\times 10^{1}\times 25}{50\times 10^{5}\left(-0.1\right)\times 10^{-3}}$$

To multiply powers of the same base, add their exponents. Add 5 and -3 to get 2.

$$B=\frac{-2\times 10^{1}\times 25}{50\times 10^{2}\left(-0.1\right)}$$

Cancel out 2\times 5\times 5 in both numerator and denominator.

$$B=\frac{-2\times 5}{-0.1\times 10^{2}}$$

Multiply -2 and 5 to get -10.

$$B=\frac{-10}{-0.1\times 10^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$B=\frac{-10}{-0.1\times 100}$$

Multiply -0.1 and 100 to get -10.

$$B=\frac{-10}{-10}$$

Divide -10 by -10 to get 1.

$$B=1$$

Assign B

$$B≔1$$