Solve B=frac{sqrt{44}+sqrt[3]{64}-15}{2^2}

$$B = \frac { \sqrt { 44 } + \sqrt[ 3 ] { 64 } - 15 } { 2 ^ { 2 } }$$

Solve for B

$$B=\frac{\sqrt{11}}{2}-\frac{11}{4}\approx -1.091687605$$

Steps for Solving Linear Equation

Factor 44=2^{2}\times 11. Rewrite the square root of the product \sqrt{2^{2}\times 11} as the product of square roots \sqrt{2^{2}}\sqrt{11}. Take the square root of 2^{2}.

$$B=\frac{2\sqrt{11}+\sqrt[3]{64}-15}{2^{2}}$$

Calculate \sqrt[3]{64} and get 4.

$$B=\frac{2\sqrt{11}+4-15}{2^{2}}$$

Subtract 15 from 4 to get -11.

$$B=\frac{2\sqrt{11}-11}{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$B=\frac{2\sqrt{11}-11}{4}$$

Divide each term of 2\sqrt{11}-11 by 4 to get \frac{1}{2}\sqrt{11}-\frac{11}{4}.

$$B=\frac{1}{2}\sqrt{11}-\frac{11}{4}$$

Assign B

$$B≔\frac{\sqrt{11}}{2}-\frac{11}{4}$$