Solve for B
B = \frac{75}{74} = 1\frac{1}{74} \approx 1.013513514
Assign B
B≔\frac{75}{74}
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B=\frac{\frac{5}{12}}{\frac{7\times 8}{3\times 15}-\frac{5}{6}}
Multiply \frac{7}{3} times \frac{8}{15} by multiplying numerator times numerator and denominator times denominator.
B=\frac{\frac{5}{12}}{\frac{56}{45}-\frac{5}{6}}
Do the multiplications in the fraction \frac{7\times 8}{3\times 15}.
B=\frac{\frac{5}{12}}{\frac{112}{90}-\frac{75}{90}}
Least common multiple of 45 and 6 is 90. Convert \frac{56}{45} and \frac{5}{6} to fractions with denominator 90.
B=\frac{\frac{5}{12}}{\frac{112-75}{90}}
Since \frac{112}{90} and \frac{75}{90} have the same denominator, subtract them by subtracting their numerators.
B=\frac{\frac{5}{12}}{\frac{37}{90}}
Subtract 75 from 112 to get 37.
B=\frac{5}{12}\times \frac{90}{37}
Divide \frac{5}{12} by \frac{37}{90} by multiplying \frac{5}{12} by the reciprocal of \frac{37}{90}.
B=\frac{5\times 90}{12\times 37}
Multiply \frac{5}{12} times \frac{90}{37} by multiplying numerator times numerator and denominator times denominator.
B=\frac{450}{444}
Do the multiplications in the fraction \frac{5\times 90}{12\times 37}.
B=\frac{75}{74}
Reduce the fraction \frac{450}{444} to lowest terms by extracting and canceling out 6.
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