Solve AH=9/16HB

$$AH = \frac{ 9 }{ 16 } HB$$

Solve for A

$$\left\{\begin{matrix}\\A=\frac{9B}{16}\text{, }&\text{unconditionally}\\A\in \mathrm{R}\text{, }&H=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$HA=\frac{9BH}{16}$$

Divide both sides by H.

$$\frac{HA}{H}=\frac{9BH}{16H}$$

Dividing by H undoes the multiplication by H.

$$A=\frac{9BH}{16H}$$

Divide \frac{9HB}{16} by H.

$$A=\frac{9B}{16}$$

Solve for B

$$\left\{\begin{matrix}\\B=\frac{16A}{9}\text{, }&\text{unconditionally}\\B\in \mathrm{R}\text{, }&H=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{9}{16}HB=AH$$

The equation is in standard form.

$$\frac{9H}{16}B=AH$$

Divide both sides by \frac{9}{16}H.

$$\frac{16\times \frac{9H}{16}B}{9H}=\frac{16AH}{9H}$$

Dividing by \frac{9}{16}H undoes the multiplication by \frac{9}{16}H.

$$B=\frac{16AH}{9H}$$

Divide AH by \frac{9}{16}H.

$$B=\frac{16A}{9}$$