Solve for A
A=3x-\beta ^{2}+5
Solve for x
x=\frac{A+\beta ^{2}-5}{3}
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A-3x=5-\beta ^{2}
Subtract \beta ^{2} from both sides.
A=5-\beta ^{2}+3x
Add 3x to both sides.
\beta ^{2}-3x=5-A
Subtract A from both sides.
-3x=5-A-\beta ^{2}
Subtract \beta ^{2} from both sides.
-3x=5-\beta ^{2}-A
The equation is in standard form.
\frac{-3x}{-3}=\frac{5-\beta ^{2}-A}{-3}
Divide both sides by -3.
x=\frac{5-\beta ^{2}-A}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{A+\beta ^{2}-5}{3}
Divide 5-A-\beta ^{2} by -3.
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