Solve Ah=1.57+(N-1)(0.15)

$$A h = 1.57 + ( N - 1 ) ( 0.15 )$$

Solve for A

$$\left\{\begin{matrix}A=\frac{\frac{3N}{20}+1.42}{h}\text{, }&h\neq 0\\A\in \mathrm{R}\text{, }&N=-\frac{142}{15}\text{ and }h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply N-1 by 0.15.

$$Ah=1.57+0.15N-0.15$$

Subtract 0.15 from 1.57 to get 1.42.

$$Ah=1.42+0.15N$$

The equation is in standard form.

$$hA=\frac{3N}{20}+1.42$$

Divide both sides by h.

$$\frac{hA}{h}=\frac{\frac{3N}{20}+1.42}{h}$$

Dividing by h undoes the multiplication by h.

$$A=\frac{\frac{3N}{20}+1.42}{h}$$

Divide 1.42+\frac{3N}{20} by h.

$$A=\frac{3N+28.4}{20h}$$

Solve for N

$$N=\frac{20Ah}{3}-\frac{142}{15}$$

Steps for Solving Linear Equation

Use the distributive property to multiply N-1 by 0.15.

$$Ah=1.57+0.15N-0.15$$

Subtract 0.15 from 1.57 to get 1.42.

$$Ah=1.42+0.15N$$

Swap sides so that all variable terms are on the left hand side.

$$1.42+0.15N=Ah$$

Subtract 1.42 from both sides.

$$0.15N=Ah-1.42$$

Divide both sides of the equation by 0.15, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.15N}{0.15}=\frac{Ah-1.42}{0.15}$$

Dividing by 0.15 undoes the multiplication by 0.15.

$$N=\frac{Ah-1.42}{0.15}$$

Divide Ah-1.42 by 0.15 by multiplying Ah-1.42 by the reciprocal of 0.15.

$$N=\frac{20Ah}{3}-\frac{142}{15}$$