A _ { 10 } = \int _ { 0 } ^ { 6 } ( \frac { - 3 x ^ { 2 } } { 2 } + 18 x ) \cdot ( \frac { 1 } { 2 } x ) d x + \int _ { 6 } ^ { 12 } ( - \frac { 3 x ^ { 2 } } { 2 } + 18 x ) \cdot ( - \frac { 1 } { 2 } x + 6 ) d x
Solve for A_10
A_{10}=810
Assign A_10
A_{10}≔810
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