Solve for A
\left\{\begin{matrix}A=\frac{D+CX-B}{X}\text{, }&X\neq 0\\A\in \mathrm{R}\text{, }&B=D\text{ and }X=0\end{matrix}\right.
Solve for B
B=D+CX-AX
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AX=CX+D-B
Subtract B from both sides.
XA=D+CX-B
The equation is in standard form.
\frac{XA}{X}=\frac{D+CX-B}{X}
Divide both sides by X.
A=\frac{D+CX-B}{X}
Dividing by X undoes the multiplication by X.
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