Solve AC^2=(8k)^2+0.515^2

$$A C ^ { 2 } = ( 8 k ) ^ { 2 } + 0.515 ^ { 2 }$$

Solve for A

$$A=\frac{2560000k^{2}+10609}{40000C^{2}}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Expand \left(8k\right)^{2}.

$$AC^{2}=8^{2}k^{2}+0.515^{2}$$

Calculate 8 to the power of 2 and get 64.

$$AC^{2}=64k^{2}+0.515^{2}$$

Calculate 0.515 to the power of 2 and get 0.265225.

$$AC^{2}=64k^{2}+0.265225$$

The equation is in standard form.

$$C^{2}A=64k^{2}+0.265225$$

Divide both sides by C^{2}.

$$\frac{C^{2}A}{C^{2}}=\frac{64k^{2}+0.265225}{C^{2}}$$

Dividing by C^{2} undoes the multiplication by C^{2}.

$$A=\frac{64k^{2}+0.265225}{C^{2}}$$

Solve for C

$$C=\frac{\sqrt{\frac{2560000k^{2}+10609}{A}}}{200}$$

$$C=-\frac{\sqrt{\frac{2560000k^{2}+10609}{A}}}{200}\text{, }A>0$$