Solve A(8,3)=3530B(2,11)

$$A ( 8,3 ) = 3530 B ( 2,11 )$$

Solve for A

$$A=\frac{74483B}{83}$$

Steps for Solving Linear Equation

Multiply 3530 and 2,11 to get 7448,3.

$$A\times 8,3=7448,3B$$

The equation is in standard form.

$$8,3A=\frac{74483B}{10}$$

Divide both sides of the equation by 8,3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{8,3A}{8,3}=\frac{74483B}{8,3\times 10}$$

Dividing by 8,3 undoes the multiplication by 8,3.

$$A=\frac{74483B}{8,3\times 10}$$

Divide \frac{74483B}{10} by 8,3 by multiplying \frac{74483B}{10} by the reciprocal of 8,3.

$$A=\frac{74483B}{83}$$

Solve for B

$$B=\frac{83A}{74483}$$

Steps for Solving Linear Equation

Multiply 3530 and 2,11 to get 7448,3.

$$A\times 8,3=7448,3B$$

Swap sides so that all variable terms are on the left hand side.

$$7448,3B=A\times 8,3$$

The equation is in standard form.

$$7448,3B=\frac{83A}{10}$$

Divide both sides of the equation by 7448,3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{7448,3B}{7448,3}=\frac{83A}{10\times 7448,3}$$

Dividing by 7448,3 undoes the multiplication by 7448,3.

$$B=\frac{83A}{10\times 7448,3}$$

Divide \frac{83A}{10} by 7448,3 by multiplying \frac{83A}{10} by the reciprocal of 7448,3.

$$B=\frac{83A}{74483}$$