Solve for A
A=\frac{3z\left(2z^{2}+1\right)}{2z+1}
z\neq -\frac{1}{2}
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2Az+A=6z^{3}+3z
Use the distributive property to multiply A by 2z+1.
\left(2z+1\right)A=6z^{3}+3z
Combine all terms containing A.
\frac{\left(2z+1\right)A}{2z+1}=\frac{6z^{3}+3z}{2z+1}
Divide both sides by 2z+1.
A=\frac{6z^{3}+3z}{2z+1}
Dividing by 2z+1 undoes the multiplication by 2z+1.
A=\frac{3z\left(2z^{2}+1\right)}{2z+1}
Divide 6z^{3}+3z by 2z+1.
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