Solve Apartialbeta+0.7x/x=0.95

$$A \frac { \partial \beta + 0.7 x } { x } = 0.95$$

Solve for A

$$A=\frac{19x}{2\left(7x+10\beta ∂\right)}$$

$$x\neq -\frac{10\beta ∂}{7}\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$A\left(∂\beta +0.7x\right)=0.95x$$

Use the distributive property to multiply A by ∂\beta +0.7x.

$$A∂\beta +0.7Ax=0.95x$$

Combine all terms containing A.

$$\left(∂\beta +0.7x\right)A=0.95x$$

The equation is in standard form.

$$\left(\beta ∂+\frac{7x}{10}\right)A=\frac{19x}{20}$$

Divide both sides by ∂\beta +0.7x.

$$\frac{\left(\beta ∂+\frac{7x}{10}\right)A}{\beta ∂+\frac{7x}{10}}=\frac{19x}{20\left(\beta ∂+\frac{7x}{10}\right)}$$

Dividing by ∂\beta +0.7x undoes the multiplication by ∂\beta +0.7x.

$$A=\frac{19x}{20\left(\beta ∂+\frac{7x}{10}\right)}$$

Divide \frac{19x}{20} by ∂\beta +0.7x.

$$A=\frac{19x}{2\left(7x+10\beta ∂\right)}$$

Solve for x

$$\left\{\begin{matrix}\\x\neq 0\text{, }&\text{unconditionally}\\x=-\frac{20A\beta ∂}{14A-19}\text{, }&∂\neq 0\text{ and }\beta \neq 0\text{ and }A\neq 0\text{ and }A\neq \frac{19}{14}\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$A\left(∂\beta +0.7x\right)=0.95x$$

Use the distributive property to multiply A by ∂\beta +0.7x.

$$A∂\beta +0.7Ax=0.95x$$

Subtract 0.95x from both sides.

$$A∂\beta +0.7Ax-0.95x=0$$

Subtract A∂\beta from both sides. Anything subtracted from zero gives its negation.

$$0.7Ax-0.95x=-A∂\beta$$

Reorder the terms.

$$0.7Ax-0.95x=-A\beta ∂$$

Combine all terms containing x.

$$\left(0.7A-0.95\right)x=-A\beta ∂$$

The equation is in standard form.

$$\left(\frac{7A}{10}-0.95\right)x=-A\beta ∂$$

Divide both sides by 0.7A-0.95.

$$\frac{\left(\frac{7A}{10}-0.95\right)x}{\frac{7A}{10}-0.95}=-\frac{A\beta ∂}{\frac{7A}{10}-0.95}$$

Dividing by 0.7A-0.95 undoes the multiplication by 0.7A-0.95.

$$x=-\frac{A\beta ∂}{\frac{7A}{10}-0.95}$$

Variable x cannot be equal to 0.

$$x=-\frac{A\beta ∂}{\frac{7A}{10}-0.95}\text{, }x\neq 0$$