Solve for A
\left\{\begin{matrix}A=-\frac{b-8}{a}\text{, }&a\neq 0\\A\in \mathrm{R}\text{, }&b=8\text{ and }a=0\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=-\frac{b-8}{A}\text{, }&A\neq 0\\a\in \mathrm{R}\text{, }&b=8\text{ and }A=0\end{matrix}\right.
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Aa=8-b
Subtract b from both sides.
aA=8-b
The equation is in standard form.
\frac{aA}{a}=\frac{8-b}{a}
Divide both sides by a.
A=\frac{8-b}{a}
Dividing by a undoes the multiplication by a.
Aa=8-b
Subtract b from both sides.
\frac{Aa}{A}=\frac{8-b}{A}
Divide both sides by A.
a=\frac{8-b}{A}
Dividing by A undoes the multiplication by A.
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