Solve A^2+18^2=60^2

$$A ^ { 2 } + 18 ^ { 2 } = 60 ^ { 2 }$$

Solve for A

$$A=6\sqrt{91}\approx 57.236352085$$

$$A=-6\sqrt{91}\approx -57.236352085$$

Steps by Finding Square Root

Calculate 18 to the power of 2 and get 324.

$$A^{2}+324=60^{2}$$

Calculate 60 to the power of 2 and get 3600.

$$A^{2}+324=3600$$

Subtract 324 from both sides.

$$A^{2}=3600-324$$

Subtract 324 from 3600 to get 3276.

$$A^{2}=3276$$

Take the square root of both sides of the equation.

$$A=6\sqrt{91} A=-6\sqrt{91}$$

Steps Using the Quadratic Formula

Calculate 18 to the power of 2 and get 324.

$$A^{2}+324=60^{2}$$

Calculate 60 to the power of 2 and get 3600.

$$A^{2}+324=3600$$

Subtract 3600 from both sides.

$$A^{2}+324-3600=0$$

Subtract 3600 from 324 to get -3276.

$$A^{2}-3276=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3276 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$A=\frac{0±\sqrt{0^{2}-4\left(-3276\right)}}{2}$$

Square 0.

$$A=\frac{0±\sqrt{-4\left(-3276\right)}}{2}$$

Multiply -4 times -3276.

$$A=\frac{0±\sqrt{13104}}{2}$$

Take the square root of 13104.

$$A=\frac{0±12\sqrt{91}}{2}$$

Now solve the equation A=\frac{0±12\sqrt{91}}{2} when ± is plus.

$$A=6\sqrt{91}$$

Now solve the equation A=\frac{0±12\sqrt{91}}{2} when ± is minus.

$$A=-6\sqrt{91}$$

The equation is now solved.

$$A=6\sqrt{91} A=-6\sqrt{91}$$