Solve A=P(1+r/100)quadtext{Solvefor}rtext{given}A=1000text{and}P=800

$$A = P ( 1 + \frac { r } { 100 } ) \quad \text { Solve for } r \text { given } A = 1000 \text { and } P = 800$$

Solve for A, P, r

$$r=25$$

$$A=1000$$

$$P=800$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$1000=800\left(1+\frac{r}{100}\right)$$

Divide both sides by 800.

$$\frac{1000}{800}=1+\frac{r}{100}$$

Reduce the fraction \frac{1000}{800} to lowest terms by extracting and canceling out 200.

$$\frac{5}{4}=1+\frac{r}{100}$$

Multiply both sides of the equation by 100, the least common multiple of 4,100.

$$125=100+r$$

Swap sides so that all variable terms are on the left hand side.

$$100+r=125$$

Subtract 100 from both sides.

$$r=125-100$$

Subtract 100 from 125 to get 25.

$$r=25$$

The system is now solved.

$$A=1000 P=800 r=25$$