Solve A=P(1+i/100)^2

$$A = P ( 1 + \frac { i } { 100 } ) ^ { 2 }$$

Solve for A

$$A=\left(\frac{9999}{10000}+\frac{1}{50}i\right)P$$

Solution Steps

Divide i by 100 to get \frac{1}{100}i.

$$A=P\left(1+\frac{1}{100}i\right)^{2}$$

Calculate 1+\frac{1}{100}i to the power of 2 and get \frac{9999}{10000}+\frac{1}{50}i.

$$A=P\left(\frac{9999}{10000}+\frac{1}{50}i\right)$$

Solve for P

$$P=\left(\frac{99990000}{100020001}-\frac{2000000}{100020001}i\right)A$$

Steps for Solving Linear Equation

Divide i by 100 to get \frac{1}{100}i.

$$A=P\left(1+\frac{1}{100}i\right)^{2}$$

Calculate 1+\frac{1}{100}i to the power of 2 and get \frac{9999}{10000}+\frac{1}{50}i.

$$A=P\left(\frac{9999}{10000}+\frac{1}{50}i\right)$$

Swap sides so that all variable terms are on the left hand side.

$$P\left(\frac{9999}{10000}+\frac{1}{50}i\right)=A$$

The equation is in standard form.

$$\left(\frac{9999}{10000}+\frac{1}{50}i\right)P=A$$

Divide both sides by \frac{9999}{10000}+\frac{1}{50}i.

$$\frac{\left(\frac{9999}{10000}+\frac{1}{50}i\right)P}{\frac{9999}{10000}+\frac{1}{50}i}=\frac{A}{\frac{9999}{10000}+\frac{1}{50}i}$$

Dividing by \frac{9999}{10000}+\frac{1}{50}i undoes the multiplication by \frac{9999}{10000}+\frac{1}{50}i.

$$P=\frac{A}{\frac{9999}{10000}+\frac{1}{50}i}$$

Divide A by \frac{9999}{10000}+\frac{1}{50}i.

$$P=\left(\frac{99990000}{100020001}-\frac{2000000}{100020001}i\right)A$$