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Solve for A, B, C
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B=2\sqrt{8}
Consider the second equation. Subtract 2 from 10 to get 8.
B=2\times 2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
B=4\sqrt{2}
Multiply 2 and 2 to get 4.
C=3\sqrt{1}
Consider the third equation. Subtract 2 from 3 to get 1.
C=3\times 1
Calculate the square root of 1 and get 1.
C=3
Multiply 3 and 1 to get 3.
A=3\sqrt{10}-5 B=4\sqrt{2} C=3
The system is now solved.