Solve A=3^{3}+3*(-1)^2011+[(-2)^3/2^-1]*2^4

$$A = 3 ^ { 3 } + 3 \cdot ( - 1 ) ^ { 2011 } + [ \frac { ( - 2 ) ^ { 3 } } { 2 ^ { - 1 } } ] \cdot 2 ^ { 4 }$$

Solve for A

$$A=-232$$

Steps for Solving Linear Equation

Calculate 3 to the power of 3 and get 27.

$$A=27+3\left(-1\right)^{2011}+\frac{\left(-2\right)^{3}}{2^{-1}}\times 2^{4}$$

Calculate -1 to the power of 2011 and get -1.

$$A=27+3\left(-1\right)+\frac{\left(-2\right)^{3}}{2^{-1}}\times 2^{4}$$

Multiply 3 and -1 to get -3.

$$A=27-3+\frac{\left(-2\right)^{3}}{2^{-1}}\times 2^{4}$$

Subtract 3 from 27 to get 24.

$$A=24+\frac{\left(-2\right)^{3}}{2^{-1}}\times 2^{4}$$

Calculate -2 to the power of 3 and get -8.

$$A=24+\frac{-8}{2^{-1}}\times 2^{4}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$A=24+\frac{-8}{\frac{1}{2}}\times 2^{4}$$

Divide -8 by \frac{1}{2} by multiplying -8 by the reciprocal of \frac{1}{2}.

$$A=24-8\times 2\times 2^{4}$$

Multiply -8 and 2 to get -16.

$$A=24-16\times 2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$A=24-16\times 16$$

Multiply -16 and 16 to get -256.

$$A=24-256$$

Subtract 256 from 24 to get -232.

$$A=-232$$

Assign A

$$A≔-232$$