Solve A=-1^3/3-1^2/2+4(-1)=

$$A = - \frac { 1 ^ { 3 } } { 3 } - \frac { 1 ^ { 2 } } { 2 } + 4 ( - 1 ) =$$

Solve for A

$$A = -\frac{29}{6} = -4\frac{5}{6} \approx -4.833333333$$

Steps for Solving Linear Equation

Calculate 1 to the power of 3 and get 1.

$$A=-\frac{1}{3}-\frac{1^{2}}{2}+4\left(-1\right)$$

Calculate 1 to the power of 2 and get 1.

$$A=-\frac{1}{3}-\frac{1}{2}+4\left(-1\right)$$

Least common multiple of 3 and 2 is 6. Convert -\frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$A=-\frac{2}{6}-\frac{3}{6}+4\left(-1\right)$$

Since -\frac{2}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{-2-3}{6}+4\left(-1\right)$$

Subtract 3 from -2 to get -5.

$$A=-\frac{5}{6}+4\left(-1\right)$$

Multiply 4 and -1 to get -4.

$$A=-\frac{5}{6}-4$$

Convert 4 to fraction \frac{24}{6}.

$$A=-\frac{5}{6}-\frac{24}{6}$$

Since -\frac{5}{6} and \frac{24}{6} have the same denominator, subtract them by subtracting their numerators.

$$A=\frac{-5-24}{6}$$

Subtract 24 from -5 to get -29.

$$A=-\frac{29}{6}$$

Assign A

$$A≔-\frac{29}{6}$$